@xixi003

Leetcode-Single Number II


题目描述

Given an array of integers, every element appears three times except for one. Find that single one.

Note:

Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?

代码

class Solution {
	public:
		int singleNumber(int A[], int n) {
		// IMPORTANT: Please reset any member data you declared, as
		// the same Solution instance will be reused for each test case.
		int once = 0;//记录%3余1的bit
		int twice = 0;//记录%3余2的bit
		for(int i = 0; i < n; i++)
		{
			twice |= once & A[i];   //或运算
			once ^= A[i];
			int not_three = ~(once & twice);
			once = not_three & once;
			twice = not_three & twice;
		}
		return once;    
		}
	};