Leetcode-Maximum Subarray

#Leetcode

题目描述

  • Find the contiguous subarray within an array (containing at least one number) which has the largest sum.
  • For example, given the array [−2,1,−3,4,−1,2,1,−5,4],the contiguous subarray [4,−1,2,1] has the largest sum = 6.
  • click to show more practice.
  • More practice:

    If you have figured out the O(n) solution, try coding another solution using the divide and conquer approach, which is more subtle.

思路

  • 扫描就行,记录下当前最大值与加上下一个之后的大小关系即可。
  • 话说,我还真的很想知道后台的判题程序是怎么跑的。研究下哈~

AC代码

#include <iostream>
#include <cstdio>

using namespace std;

int maxSubArray(int A[], int n)
{
    	if(n == 0)
    		return 0;
    	int curSum = A[0];
    	int maxSum = curSum;
    	for(int i = 1; i < n; ++i)
    	{
    		if(curSum + A[i] > A[i])
    			curSum = curSum + A[i];
    		else
    			curSum = A[i];
    		maxSum = (maxSum > curSum ? maxSum : curSum);
    	}
    	return maxSum;
}

int main()
{
    	int n;
    	cin>>n;
    	int A[n];
    	for(int i = 0; i < n; i++)
    		cin>>A[i];
    	cout<<maxSubArray(A,n)<<endl;
    	return 0;
}